若a=
|
∵a=
,b=ln2 2
,c=ln3 3
,ln5 5
∴b-a=
-ln3 3
=ln2 2
=2ln3-3ln2 6
>0ln9-ln8 6
a-c=
-ln2 2
=ln5 5
=5ln2-2ln5 10
>0ln32-ln25 10
即b>a,a>c
∴c<a<b
故答案为:c<a<b
若a=
|
∵a=
,b=ln2 2
,c=ln3 3
,ln5 5
∴b-a=
-ln3 3
=ln2 2
=2ln3-3ln2 6
>0ln9-ln8 6
a-c=
-ln2 2
=ln5 5
=5ln2-2ln5 10
>0ln32-ln25 10
即b>a,a>c
∴c<a<b
故答案为:c<a<b