(lg5)2+lg50•lg2=( )
A.0
B.1
C.2
D.4
原式=(lg5)2+lg(10×5)lg2
=(lg5)2+(1+lg5)lg2
=(lg5)2+lg5lg2+lg2
=lg5(lg5+lg2)+lg2
=lg5lg10+lg2
=lg5+lg2
=1.
故选B.
(lg5)2+lg50•lg2=( )
A.0
B.1
C.2
D.4
原式=(lg5)2+lg(10×5)lg2
=(lg5)2+(1+lg5)lg2
=(lg5)2+lg5lg2+lg2
=lg5(lg5+lg2)+lg2
=lg5lg10+lg2
=lg5+lg2
=1.
故选B.