问题 解答题
巧解密码:
(1)(3X+2)+2[(X-1)-(2X+1)]=6
(2)若
1
2
X:7.5=0.16:1
7
8
,求75X+8的值.
答案

(1)(3X+2)+2[(X-1)-(2X+1)]=6,

3x+2+2(-x-2)=6,

3x+2-2x-4=6,

x-2=6,

x-2+2=6+2,

x=8;

(2)

1
2
X:7.5=0.16:1
7
8

1
2
x×1
7
8
=7.5×0.16,

15
16
x=1.2,

15
16
x÷
15
16
=1.2÷
15
16

x=1

7
25

75×1

7
25
+8,

=96+8,

=104.

单项选择题
单项选择题