(1)求值:lg2lg50+lg5lg20-log34log23lg2lg5;
(2)已知log56=a,log54=b.用a,b表示log2512.
(1)lg2•lg50+lg5•lg20-log34•log23•lg2•lg5
=lg2(lg5+1)+lg5(lg2+1)-
log23lg2lg5log24 log23
=lg2lg5+lg2+lg5lg2+lg5-2lg2lg5
=lg2+lg5
=1
(2)log2512=log512 log525
=log56+
log541 2 2
=
=a+
b1 2 2
.2a+b 4