问题
解答题
计算:
(1)2log510+log50.25;
(2)31+log35-24+log23+103lg3+2-log25.
答案
(1)原式=log5(102×0.25)=log525=2;
(2)原式=3×3log35-24×2log23+10lg33+2log25-1=3×5-16×3+27+
=15-48+27+1 5
=-1 5
.29 5
计算:
(1)2log510+log50.25;
(2)31+log35-24+log23+103lg3+2-log25.
(1)原式=log5(102×0.25)=log525=2;
(2)原式=3×3log35-24×2log23+10lg33+2log25-1=3×5-16×3+27+
=15-48+27+1 5
=-1 5
.29 5