(1)计算log256.25+lg0.01+ln
(2)x=log23求
|
(1)原式=2-2+
+2×3=1 2
;13 2
(2)∵x=log23,∴2x=3,
∴
=23x-2-3x 2x-2-x
=(2x)3-(2x)-3 2x-(2x)-1
=33-3-3 3-3-1
.91 9
(1)计算log256.25+lg0.01+ln
(2)x=log23求
|
(1)原式=2-2+
+2×3=1 2
;13 2
(2)∵x=log23,∴2x=3,
∴
=23x-2-3x 2x-2-x
=(2x)3-(2x)-3 2x-(2x)-1
=33-3-3 3-3-1
.91 9