问题 解答题
计算下列各式:
(1)2log32-log3
32
9
+log38-52log53

(2)
8n+1(
1
2
)
2n+1
4n8-2
答案

(1)2log32-log3

32
9
+log38-52log53

=2log32-(log332-log39)+3log32-5log59

=2log32-5log32+2+3log32-9

=log3[(4×8)÷32]-7

=-7.

(2)

8n+1(
1
2
)
2n+1
4n8-2

=

23n+3
1
22n+1
22n2-6

=23n+3-2n-1-2n+6

=28-n

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