问题 解答题
求值:
(1)log3
1
9
+lg25+lg4+ln
e

(2)已知
tanθ=3 ,求2sinθcosθ+cos2θ
的值.
答案

(1)

log3
1
9
+lg25+lg4+ln
e

=-2+lg100+

1
2
lne

=-2+2+

1
2

=

1
2

(2)因为

tanθ=3 

2sinθcosθ+cos2θ

=

2sinθcosθ+cos2θ
sin2θ+cos2θ

=

2tanθ+1
tan2θ+1

=

2×3+1
32+1

=

7
10

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