问题 解答题
计算:
(1)log89•log32+lg5lg20+(lg2)2
(2)已知cos(75°+α)=
1
3
,其中-180°<α<-90°,求sin(105°-α)+cos(375°-α)的值.
答案

(1)原式=

2lg3
3lg2
lg2
lg3
+(1-lg2)(1+lg2)+(lg2)2=
2
3
+1=
5
3

(2)sin(105°-α)=sin(75°+α);

cos(375°-α)=cos(15°-α)=sin(75°+α);

∵-180°<α<-90⇒-105°<α<-15°,∴sin(75°+α)=-

2
2
3

∴原式=sin(105°-α)+cos(375°-α)=2sin(75°+α)=-

4
2
3

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