问题
解答题
计算: (1)log89•log32+lg5lg20+(lg2)2 (2)已知cos(75°+α)=
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答案
(1)原式=
•2lg3 3lg2
+(1-lg2)(1+lg2)+(lg2)2=lg2 lg3
+1=2 3
.5 3
(2)sin(105°-α)=sin(75°+α);
cos(375°-α)=cos(15°-α)=sin(75°+α);
∵-180°<α<-90⇒-105°<α<-15°,∴sin(75°+α)=-
.2 2 3
∴原式=sin(105°-α)+cos(375°-α)=2sin(75°+α)=-
.4 2 3