问题 解答题
化简求值:
(1)(2
7
9
)0.5+0.1-2-π0+
1
3

(2)(lg2)2+lg2lg5+
(lg2)2-lg4+1
答案

(1)(2

7
9
)0.5+0.1-2-π0+
1
3

=(

25
9
)
1
2
+100-1+
1
3

=

5
3
+100-1+
1
3
=101;                     

(2)(lg2)2+lg2lg5+

(lg2)2-lg4+1

=lg2(lg2+lg5)+

(lg2-1)2

=lg2+(1-lg2)=1.

单项选择题
单项选择题