问题
填空题
(1)已知
|
答案
(1)∵
=a b
,∴a=3 2
b,∴原式=3 2
=
b-b3 2 b
;1 2
(2)∵
=y x+2y
,∴x=2y,∴1 4
=2.x y
故答案为:
,2.1 2
(1)已知
|
(1)∵
=a b
,∴a=3 2
b,∴原式=3 2
=
b-b3 2 b
;1 2
(2)∵
=y x+2y
,∴x=2y,∴1 4
=2.x y
故答案为:
,2.1 2