问题
解答题
化简①式,求②的值: ①
②log3
|
答案
①原式=x-
+1-2 3
•y1 3
-1 2
+1 2
=y1 6
.1 6
②原式=
log333+lg(25×4)+2+11 2
=
+2+2+1=3 2
.13 2
化简①式,求②的值: ①
②log3
|
①原式=x-
+1-2 3
•y1 3
-1 2
+1 2
=y1 6
.1 6
②原式=
log333+lg(25×4)+2+11 2
=
+2+2+1=3 2
.13 2