问题 解答题
计算:
(1)(
32
×
3
)6
+(
2
4
3
-(-2008)0
(2)lg
1
2
-lg
5
8
+lg12.5-log89×log278.
答案

(1)原式=2

1
3
×6×3
1
2
×6
+(2
1
2
×2
1
4
)
4
3
-1

=22×33+2

3
4
×
4
3
-1

=108+2-1

=109;

(2)原式=lg(

1
2
÷
5
8
×12.5)-
lg9
lg8
×
lg8
lg27

=lg(

1
2
×
8
5
×
25
2
)-
2lg3
3lg2
×
3lg2
3lg3

=lg10-

2
3

=1-

2
3

=

1
3

单项选择题
单项选择题