问题
填空题
将(
|
答案
∵(
)0=1,1 6
>1,log22
=-1,-1=log0.52<log0.51 2
<0,3 2
∴log2
<log0.51 2
<(3 2
)0<1 6
.2
故答案为:∴log2
<log0.51 2
<(3 2
)0<1 6
.2
将(
|
∵(
)0=1,1 6
>1,log22
=-1,-1=log0.52<log0.51 2
<0,3 2
∴log2
<log0.51 2
<(3 2
)0<1 6
.2
故答案为:∴log2
<log0.51 2
<(3 2
)0<1 6
.2