问题
解答题
计算: (1)(2-3)0-(
(2)2(a4)3-a2a10+(-2a5)2÷a2 (3)(x-1)(x-2)-3x(x+3)+2(x+2)(x-1),其中x=
|
答案
(1)原式=1-4+(-
×4)20101 4
=-3+1
=-2;
(2)原式=2a12-a12+4a10÷a2
=a12+4a8;
(3)原式=x2-3x+2-3x2-9x+2x2+2x-4
=-10x-2,
当x=
时,原式=-1 3
-2=-10 3
.16 3