计算: (1)
(2)[
|
(1)
-sin60°+(-22
-13
)0-5 12 4
=
-2(
+1)3 (
-1)(3
+1)3
+1-3 2 2 3 4
=
+1-3
+1-3 2 3 2
=
+2;3
(2)原式=[
-(a+1)(a-2) (a-2)2
]÷a a(a-2) a a-2
=(
-a+1 a-2
)•1 a-2 a-2 a
=
•a a-2 a-2 a
=1.
计算: (1)
(2)[
|
(1)
-sin60°+(-22
-13
)0-5 12 4
=
-2(
+1)3 (
-1)(3
+1)3
+1-3 2 2 3 4
=
+1-3
+1-3 2 3 2
=
+2;3
(2)原式=[
-(a+1)(a-2) (a-2)2
]÷a a(a-2) a a-2
=(
-a+1 a-2
)•1 a-2 a-2 a
=
•a a-2 a-2 a
=1.