问题 解答题
计算:
(1)
2
3
-1
-sin60°+(-2
5
0-
12
4

(2)[
(a+1)(a-2)
a2-4a+4
-
a
a2-2a
a
a-2
答案

(1)

2
3
-1
-sin60°+(-2
5
0-
12
4

=

2(
3
+1)
(
3
-1)(
3
+1)
-
3
2
+1-
2
3
4

=

3
+1-
3
2
+1-
3
2

=

3
+2;

(2)原式=[

(a+1)(a-2)
(a-2)2
-
a
a(a-2)
a
a-2

=(

a+1
a-2
-
1
a-2
)•
a-2
a

=

a
a-2
a-2
a

=1.

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