问题
解答题
(1)计算:(
(2)先化简(1+
|
答案
(1)原式=1+2+6=9;
(2)原式=
•a2 (a+2)(a-2)
=a+2 a
. a a-2
∵a(a+2)(a-2)≠0,
∴a≠0,a≠2且a≠-2.
∴当a=1时,原式=
=-1.1 1-2
(1)计算:(
(2)先化简(1+
|
(1)原式=1+2+6=9;
(2)原式=
•a2 (a+2)(a-2)
=a+2 a
. a a-2
∵a(a+2)(a-2)≠0,
∴a≠0,a≠2且a≠-2.
∴当a=1时,原式=
=-1.1 1-2