问题
解答题
(1)计算:(
(2)已知a=
|
答案
(1)原式=3-
+1+2×2 2 2
=4
(2)∵a=
,b=1 1+ 2
,1 1- 2
∴a=-1+
,b=-1-2
,2
∴a+b=-2,ab=-1,
∵a2b+ab2=ab(a+b)
=-1×(-2),
=2.
(1)计算:(
(2)已知a=
|
(1)原式=3-
+1+2×2 2 2
=4
(2)∵a=
,b=1 1+ 2
,1 1- 2
∴a=-1+
,b=-1-2
,2
∴a+b=-2,ab=-1,
∵a2b+ab2=ab(a+b)
=-1×(-2),
=2.