问题 解答题
(1)计算:2-2+|-
1
4
|-(π-2013)0

(2)化简:(
1
2
-
a
2a+2
a
a+1
答案

(1)2-2+|-

1
4
|-(π-2013)0

=

1
4
+
1
4
-1

=-

1
2

(2)(

1
2
-
a
2a+2
a
a+1

=

1
2
×
a+1
a
-
a
2(a+1)
×
a+1
a

=

a+1
2a
-
1
2

=

a+1
2a
-
a
2a

=

1
2a

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