问题
解答题
(1)计算:2-2+|-
(2)化简:(
|
答案
(1)2-2+|-
|-(π-2013)01 4
=
+1 4
-11 4
=-
;1 2
(2)(
-1 2
)÷a 2a+2 a a+1
=
×1 2
-a+1 a
×a 2(a+1) a+1 a
=
-a+1 2a 1 2
=
-a+1 2a a 2a
=
.1 2a
(1)计算:2-2+|-
(2)化简:(
|
(1)2-2+|-
|-(π-2013)01 4
=
+1 4
-11 4
=-
;1 2
(2)(
-1 2
)÷a 2a+2 a a+1
=
×1 2
-a+1 a
×a 2(a+1) a+1 a
=
-a+1 2a 1 2
=
-a+1 2a a 2a
=
.1 2a