问题 解答题
(1)计算①(-
1
3
)-2-16÷(-2)3+(π-
3
2
)0-2
3
×
3

6
1
4
+
33+
3
8
+|
2
-
3
|-
3
-
(-4)2

(2)因式分ax2-2ax+a;
(3)先化简,再求值:
a+1
a-1
-
a
a2-2a+1
÷
1
a
,其中a=1-
2
答案

(1)①原式=9-16÷(-8)+1-6=9+2+1-6=6;

②原式=

5
2
+
3
2
+
3
-
2
-
3
-4=-
2

(2)原式=a(x2-2x+1)=a(x-1)2

(3)原式=

a+1
a-1
-
a2
(a-1)2
=
(a+1)(a-1)
(a-1)2
-
a2
(a-1)2
=-
1
(a-1)2

当a=1-

2
时,原式=-
1
(1-
2
-1)2
=-
1
2

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