问题
解答题
(1)计算①(-
②
(2)因式分ax2-2ax+a; (3)先化简,再求值:
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答案
(1)①原式=9-16÷(-8)+1-6=9+2+1-6=6;
②原式=
+5 2
+3 2
-3
-2
-4=-3
;2
(2)原式=a(x2-2x+1)=a(x-1)2;
(3)原式=
-a+1 a-1
=a2 (a-1)2
-(a+1)(a-1) (a-1)2
=-a2 (a-1)2
,1 (a-1)2
当a=1-
时,原式=-2
=-1 (1-
-1)22
.1 2