问题 填空题
已知Sn,Tn分别是等差数列{an},{bn}的前n项和,且
Sn
Tn
=
2n+1
4n-2
,(n∈N+)则
a10
b3+b18
+
a11
b6+b15
=______.
答案

∵Sn,Tn分别是等差数列{an},{bn}的前n项和,

Sn
Tn
=
2n+1
4n-2
,(n∈N+),

a10
b3+b18
+
a11
b6+b15
=
a10+a11
b10+b11

=

S20
T20
=
40+1
80-2
=
41
78

故答案为:

41
78

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