问题
填空题
数列{an}满足an+an+1=
|
答案
∵an+an+1=
(n∈N*),a1+a2=a2+a3,1 2
∴a1=a3,
a3+a4=a4+a5
∴a1=a3=a5=…=a2n-1,
即奇数项都相等
∴a21=a1=1
∴S21=(a1+a2)+(a3+a4)+…+(a19+a20)+a21
=10×
+11 2
=6.
答案:6.
数列{an}满足an+an+1=
|
∵an+an+1=
(n∈N*),a1+a2=a2+a3,1 2
∴a1=a3,
a3+a4=a4+a5
∴a1=a3=a5=…=a2n-1,
即奇数项都相等
∴a21=a1=1
∴S21=(a1+a2)+(a3+a4)+…+(a19+a20)+a21
=10×
+11 2
=6.
答案:6.