数列1
|
由于Sn=1
+31 2
+51 4
+71 8
+…+[(2n-1)+1 16
]1 2n
=[1+3+5+7+…+(2n-1)]+(
+1 2
+1 4
+…+1 8
)1 2n
=n+
×2+n(n-1) 2
(1-1 2
)1 2n 1- 1 2
=n2+1-1 2n
则Sn=n2+1-1 2n
故答案为 A.
数列1
|
由于Sn=1
+31 2
+51 4
+71 8
+…+[(2n-1)+1 16
]1 2n
=[1+3+5+7+…+(2n-1)]+(
+1 2
+1 4
+…+1 8
)1 2n
=n+
×2+n(n-1) 2
(1-1 2
)1 2n 1- 1 2
=n2+1-1 2n
则Sn=n2+1-1 2n
故答案为 A.