问题 选择题
数列{an}中,an=
1
n(n+1)
,若{an}的前n项和为
2010
2011
,则项数n为(  )
A.2008B.2009C.2010D.2011
答案

∵an=

1
n(n+1)
1
n
-
1
n+1

Sn=a1+a2+…+an

=1-

1
2
+
1
2
-
1
3
+…+
1
n
-
1
n+1

=1-

1
n+1
=
n
n+1
=
2010
2011

∴n=2010

故选C

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