问题
解答题
计算:(x-1-y-1)÷(x-2-y-2)-xy(x+y)-1.
答案
原式=(
-1 x
)÷(1 y
-1 x2
)-1 y2 xy x+y
=
÷y-x xy
-(y-x)(y+x) x2y2 xy x+y
=
×y-x xy
-x2y2 (y-x)(y+x) xy x+y
=
-xy y+x xy x+y
=0.
计算:(x-1-y-1)÷(x-2-y-2)-xy(x+y)-1.
原式=(
-1 x
)÷(1 y
-1 x2
)-1 y2 xy x+y
=
÷y-x xy
-(y-x)(y+x) x2y2 xy x+y
=
×y-x xy
-x2y2 (y-x)(y+x) xy x+y
=
-xy y+x xy x+y
=0.