问题 解答题
(1)计算:-12012+(
1
2
)
-2
-(tan62°+
2
π
)
0
+|
27
-8sin60°|

(2)先化简,再求值:(
a2-5a+2
a+2
+1
)•
a2-4
a2+4a+4
,其中,a=2+
3
答案

(1)原式=-1+4-1+|3

3
-8×
3
2
|

=-1+4-1+

3

=2+

3

(2)原式=

a2-5a+2+a+2
a+2
(a+2)2
(a+2)(a-2)

=

(a-2)2
a+2
(a+2)2
(a+2)(a-2)

=a-2,

a=2+

3
时,原式=2+
3
-2=
3

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