问题 解答题
计算:
(1)-12010-(1-0.5)÷3×[2-(-3)2];
(2)-(
1
2
)2+2-1×(
2
3
-|
2
3
-2|)

(3)
1
2
+1
+|
2
-
3
|-2×
3
2
+(π-3.14)0

(4)
(-2)2
+(-
1
3
)-2×(-
1
2
)3-
27
-
2
3
+1

(5)(
7
9
-
5
6
+
7
18
)×18-1.45×6+3.95×6
答案

(1)原式=-1-0.5÷3×(2-9)

=-1-0.5÷3×(-7)

=-1+

7
6

=

1
6

(2)原式=-

1
4
+
1
2
×(
2
3
-
4
3

=-

1
4
+
1
2
×(-
2
3

=-

1
4
-
1
3

=-

1
12

(3)原式=

2
-1+
3
-
2
-
3
+1

=0;

(4)原式=2+9×(-

1
8
)-3-(
3
-1)

=2-

9
8
-3-
3
+1

=-

9
8
-
3

(5)原式=

14
18
-
15
18
+
7
18

=

14-15+7
18

=

6
18

=

1
3

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