问题
填空题
数列{an}的通项公式是an=
|
答案
∵an=
1 |
n(n+1) |
1 |
n |
1 |
n+1 |
∴Sn=a1+a2+…+an
=1-
1 |
2 |
1 |
2 |
1 |
3 |
1 |
n |
1 |
n+1 |
=1-
1 |
n+1 |
n |
n+1 |
∴
n |
n+1 |
10 |
11 |
∴n=10
故答案为:10
数列{an}的通项公式是an=
|
∵an=
1 |
n(n+1) |
1 |
n |
1 |
n+1 |
∴Sn=a1+a2+…+an
=1-
1 |
2 |
1 |
2 |
1 |
3 |
1 |
n |
1 |
n+1 |
=1-
1 |
n+1 |
n |
n+1 |
∴
n |
n+1 |
10 |
11 |
∴n=10
故答案为:10