问题
填空题
化简
|
答案
原式=
×4a2b3 (x-1)2
×-(x-1)(x+1) 6ab 1 a2b2
=
×-2ab2(x+1) 3(x-1) 1 a2b2
=-
．2(x+1) 3a(x-1)
故答案为：-
．2(x+1) 3a(x-1)
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化简
|
原式=
×4a2b3 (x-1)2
×-(x-1)(x+1) 6ab 1 a2b2
=
×-2ab2(x+1) 3(x-1) 1 a2b2
=-
．2(x+1) 3a(x-1)
故答案为：-
．2(x+1) 3a(x-1)