问题
填空题
化简
|
答案
原式=
| 4a2b3 |
| (x-1)2 |
| -(x-1)(x+1) |
| 6ab |
| 1 |
| a2b2 |
=
| -2ab2(x+1) |
| 3(x-1) |
| 1 |
| a2b2 |
=-
| 2(x+1) |
| 3a(x-1) |
故答案为：-
| 2(x+1) |
| 3a(x-1) |
搜题请搜索小程序“爱下问搜题”
化简
|
原式=
| 4a2b3 |
| (x-1)2 |
| -(x-1)(x+1) |
| 6ab |
| 1 |
| a2b2 |
=
| -2ab2(x+1) |
| 3(x-1) |
| 1 |
| a2b2 |
=-
| 2(x+1) |
| 3a(x-1) |
故答案为：-
| 2(x+1) |
| 3a(x-1) |