问题
填空题
设Sn=
|
答案
由于
=1 n(n+1)
-1 n 1 n+1
Sn=
+1 2
+…+1 6
=1-1 n(n+1)
+1 2
-1 2
+…+1 3
-1 n 1 n+1
=1-
=1 n+1 n n+1
Sn•Sn+1=
•n n+1
=n+1 n+2
=n n+2 3 4
∴n=6
故答案为:6
设Sn=
|
由于
=1 n(n+1)
-1 n 1 n+1
Sn=
+1 2
+…+1 6
=1-1 n(n+1)
+1 2
-1 2
+…+1 3
-1 n 1 n+1
=1-
=1 n+1 n n+1
Sn•Sn+1=
•n n+1
=n+1 n+2
=n n+2 3 4
∴n=6
故答案为:6