问题
解答题
(1)计算:|-3|-
(2)计算:(
|
答案
(1)原式=3-2+1-3
=-1;
(2)原式=
•2a(a+1)-a(a-1) (a-1)(a+1) (a+1)(a-1) a
=
•a(a+3) (a-1)(a+1) (a+1)(a-1) a
=a+3.
(1)计算:|-3|-
(2)计算:(
|
(1)原式=3-2+1-3
=-1;
(2)原式=
•2a(a+1)-a(a-1) (a-1)(a+1) (a+1)(a-1) a
=
•a(a+3) (a-1)(a+1) (a+1)(a-1) a
=a+3.