问题
填空题
计算: (1)(-a2)3•a6÷(-a3)4=______; (2)(
|
答案
(1)原式=-a6•a6÷a12
=-a12÷a12
=-1;
(2)原式=22012×(-
)2010+11 2
=22×22010×(-
)2010+11 2
=4×[2×(-
)]2010+11 2
=4+1
=5.
故答案为:-1;5
计算: (1)(-a2)3•a6÷(-a3)4=______; (2)(
|
(1)原式=-a6•a6÷a12
=-a12÷a12
=-1;
(2)原式=22012×(-
)2010+11 2
=22×22010×(-
)2010+11 2
=4×[2×(-
)]2010+11 2
=4+1
=5.
故答案为:-1;5