问题 选择题

三个数20110.99,0.992011,log0.992011的大小关系为(  )

A.log0.992011<0.992011<20110.99

B.log0.992011<20110.99<0.992011

C.0.992011<log0.992011<20110.99

D.0.992011<20110.99<log0.992011

答案

设f(x)=2011x,g(x)=0.99x,h(x)=log0.99x

则f(x)单调递增,g(x)单调递减,h(x)单调递减

∴f(0.99)=20110.99>20110=1

0<g(2011)=0.992011<0.990=1

h(2011)=log0.992011<log0.991=0

即20110.99>1,0<0.992011<1,log0.992011<0

∴log0.992011<0.992011<20110.99

故选A

单项选择题
问答题 简答题