问题
解答题
计算: (1)(-
(2)2(m+1)2-(2m+1)(2m-1) |
答案
(1)原式=1-27-(
×5)20111 5
=1-27-1
=-27;
(2)原式=2m2+4m+2-4m2+1
=-2m2+4m+3.
计算: (1)(-
(2)2(m+1)2-(2m+1)(2m-1) |
(1)原式=1-27-(
×5)20111 5
=1-27-1
=-27;
(2)原式=2m2+4m+2-4m2+1
=-2m2+4m+3.