问题
解答题
(1)计算(π+1)0-
(2)若a=1-
|
答案
(1)原式=1-2
+23 3
=1;
(2)原式=
+(a+1)(a-1) a(a+1) 1-a a(a-1)
=
-a-1 a 1 a
=a-2 a
当a=1-
时,原式=2
=1-
-22 1- 2
=-
-12 1- 2
=
+12
-12
3+2(
+1)22 (
-1)(2
+1)2
..2
(1)计算(π+1)0-
(2)若a=1-
|
(1)原式=1-2
+23 3
=1;
(2)原式=
+(a+1)(a-1) a(a+1) 1-a a(a-1)
=
-a-1 a 1 a
=a-2 a
当a=1-
时,原式=2
=1-
-22 1- 2
=-
-12 1- 2
=
+12
-12
3+2(
+1)22 (
-1)(2
+1)2
..2