问题 选择题
等差数列{an}中,若a1=1,a8=15,则
1
a1a2
+
1
a2a3
+
+
1
a100a101
=(  )
A.
200
199
B.
100
199
C.
200
201
D.
100
201
答案

设等差数列的公差为d,

∵a1=1,a8=15,

∴a8=a1+7d=15,

解得d=2,

∴等差数列的通项公式an=2n-1,

1
anan+1
=
1
(2n-1)(2n+1)
=
1
2
1
2n-1
-
1
2n+1
),

1
a1a2
+
1
a2a3
+…+
1
a100a101
=
1
2
(1-
1
201
)=
100
201

故选D.

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