问题
解答题
(1)计算:(-2-2+
(2)计算:
|
答案
(1)原式=(-
+1 4
)×121 3
-1÷2
=2 2
×121 12
-1×2
=0;2
(2)原式=
•m+1 2m(m-1)
-4m2 (m+1)2 m+1-(m-1) (m-1)(m+1)
=
-2m (m-1)(m+1) 2 (m-1)(m+1)
=
=2(m-1) (m-1)(m+1)
.2 (m+1)
(1)计算:(-2-2+
(2)计算:
|
(1)原式=(-
+1 4
)×121 3
-1÷2
=2 2
×121 12
-1×2
=0;2
(2)原式=
•m+1 2m(m-1)
-4m2 (m+1)2 m+1-(m-1) (m-1)(m+1)
=
-2m (m-1)(m+1) 2 (m-1)(m+1)
=
=2(m-1) (m-1)(m+1)
.2 (m+1)