问题 解答题
(1)计算:(-2-2+
1
3
)×6
8
-20080÷sin 45°;
(2)计算:
m+1
2m2-2m
•(
2m
m+1
)2-(
1
m-1
-
1
m+1
)
答案

(1)原式=(-

1
4
+
1
3
)×12
2
-1÷
2
2
=
1
12
×12
2
-1×
2
=0;

(2)原式=

m+1
2m(m-1)
4m2
(m+1)2
-
m+1-(m-1)
(m-1)(m+1)

=

2m
(m-1)(m+1)
-
2
(m-1)(m+1)

=

2(m-1)
(m-1)(m+1)
=
2
(m+1)

单项选择题
单项选择题