问题
解答题
计算: (1)(-1)2009+|-
(2)6tan230°-
|
答案
(1)原式=-1+
-2-3 2 3 2
=-3;
(2)原式=6×(
)2-3 3
×3
-2×3 2 2 2
=6×
-1 3
-3 2 2
=2-
-3 2 2
=
-1 2
.2
计算: (1)(-1)2009+|-
(2)6tan230°-
|
(1)原式=-1+
-2-3 2 3 2
=-3;
(2)原式=6×(
)2-3 3
×3
-2×3 2 2 2
=6×
-1 3
-3 2 2
=2-
-3 2 2
=
-1 2
.2