计算: (1)
(2)
(3)(解方程)x2-4x-1=0 (4)在Rt△ABC中,∠C=90°,c=30,∠A=60°,求:a,b. |
(1)
-(-2009)0+(12
)-2+|1-1 2
|3
=2
-1+4+3
-13
=3
+2;3
(2)
•b2a a b
=ba2
=a
;b
(3)x2-4x-1=0,
a=1,b=-4,c=-1,
x=
=2±4± 16+4 2
,5
故x1=2+
,x2=2-5
;5
(4)∵在Rt△ABC中,∠C=90°,c=30,∠A=60°,
∴∠B=30°,
∴b=15,
a=15
.3