已知数列{an}满足a1=2,an+1=
|
由a1=2,an+1=
5an-13 |
3an-7 |
5×2-13 |
3×2-7 |
5×3-13 |
3×3-7 |
5×1-13 |
3×1-7 |
5×2-13 |
3×2-7 |
所以数列{an}是周期为3的数列.
故s100=a1+a2+a3+…+a100=33(a1+a2+a3)+a1=33(2+3+1)+2=200.
故答案为:200.
已知数列{an}满足a1=2,an+1=
|
由a1=2,an+1=
5an-13 |
3an-7 |
5×2-13 |
3×2-7 |
5×3-13 |
3×3-7 |
5×1-13 |
3×1-7 |
5×2-13 |
3×2-7 |
所以数列{an}是周期为3的数列.
故s100=a1+a2+a3+…+a100=33(a1+a2+a3)+a1=33(2+3+1)+2=200.
故答案为:200.