问题
解答题
(1)(-π)0+
(2)(x-2)2-2(x-2)+1=0. |
答案
(1)原式=1+
-2 2
×21 4
+2
+2-3 2 3
=1+
-2 2
+2 2
+2-3 2 3
=3-
;3 2
(2)方程变形为(x-2-1)2=0,
开方得:x-3=0,
则x1=x2=3.
(1)(-π)0+
(2)(x-2)2-2(x-2)+1=0. |
(1)原式=1+
-2 2
×21 4
+2
+2-3 2 3
=1+
-2 2
+2 2
+2-3 2 3
=3-
;3 2
(2)方程变形为(x-2-1)2=0,
开方得:x-3=0,
则x1=x2=3.