问题
填空题
{an}是等差数列,满足
|
答案
=λAB AC
这意味着A,B,C三点共线
=pOC
+qOA OB
满足p+q=1
对比原式
a1005+a1006=1
S2010=2010(a1+a2010)/2
=1005(a1005+a1006)
=1005
故答案为1005
{an}是等差数列,满足
|
=λAB AC
这意味着A,B,C三点共线
=pOC
+qOA OB
满足p+q=1
对比原式
a1005+a1006=1
S2010=2010(a1+a2010)/2
=1005(a1005+a1006)
=1005
故答案为1005