问题
解答题
(1)计算:3tan30°+|3-π|-
(2)先化简,再求值:(
|
答案
(1)原式=3×
+π-3-3 3
-13
=
+π-3-3
-13
=π-4;
(2)原式=
×3x(x-1)-x(x+1) (x+1)(x-1) (x+1)(x-1) x-2
=2x(x-2) x-2
=2x.
(1)计算:3tan30°+|3-π|-
(2)先化简,再求值:(
|
(1)原式=3×
+π-3-3 3
-13
=
+π-3-3
-13
=π-4;
(2)原式=
×3x(x-1)-x(x+1) (x+1)(x-1) (x+1)(x-1) x-2
=2x(x-2) x-2
=2x.