问题
填空题
数列{an}的通项公式为an=
|
答案
∵an=
=1 n(n+1)
-1 n 1 n+1
∴S100=1-
+1 2
-1 2
+…+1 3
-1 100 1 101
=1-
=1 101 100 101
故答案为:100 101
数列{an}的通项公式为an=
|
∵an=
=1 n(n+1)
-1 n 1 n+1
∴S100=1-
+1 2
-1 2
+…+1 3
-1 100 1 101
=1-
=1 101 100 101
故答案为:100 101