问题 解答题
(1)计算:16÷(-2)3+(2009-
π
6
)0-|tan60°-1|+(
1
3
)-1×
2
3

(2)先化简,再求值
x2-2x
x2-1
÷(x-1-
2x-1
x+1
)
,其中x=
1
2
答案

(1)原式=-16÷8+1-(

3
-1)+3×
2
3
3

=-2+1-

3
+1+2
3

=

3
…(8分)

(2)原式=

x(x-2)
(x+1)(x-1)
÷
x2-1-2x+1
x+1

=

x(x-2)
(x+1)(x-1)
x+1
x(x-2)

=

1
x-1

x=

1
2
时,原式=-2.…(8分)

选择题
单项选择题 A3/A4型题