问题
选择题
已知数列{an}满足:a1=
|
答案
又因为an+1=an2+an,即an+1-an =an2>0,所以数列是增数列,
并且
>0,1 an
又因为an+1=an2+an,即an+1=an (1+an),
=1 an+1
=1 an•(1+an)
-1 an 1 1+an
所以
=1 an+1
-1 an
,即1 an+1
=1 an+1
-1 an
,1 an+1
+1 a1+1
+…+1 a2+1 1 a2011+1
=
-1 a1
+1 a2
-1 a2
+…+1 a3
-1 a2010 1 a2011
=
-1 a1
<1 a2011
=2,1 a1
a1=
,a2=1 2
,a3=3 4
,16 21
+1 a1+1
=1 a2+1
+2 3
>1.4 7
所以
+1 a1+1
+…+1 a2+1
∈(1,2).1 a2011+1
所以[
+1 a1+1
+…+1 a2+1
]=1.1 a2011+1
故选B.