问题
解答题
计算：(
|
答案
(
)-1+16÷(-2)3+(2011-1 3
)0-π 3
•tan60°3
=
+16÷（-8）+1-1 1 3
×3 3
=3-2+1-3
=-1．
搜题请搜索小程序“爱下问搜题”
计算：(
|
(
)-1+16÷(-2)3+(2011-1 3
)0-π 3
•tan60°3
=
+16÷（-8）+1-1 1 3
×3 3
=3-2+1-3
=-1．