已知4a=8,2m=9n=36,且
|
∵4a=8∴22a=23,
又∵f(x)=2x为单调递增的函数
∵a=
,3 2
∵2m=9n=36,
∴m=log236,n=log936
又∵
+1 m
=b,1 2n
∴b=
+1 log236
=log362+1 2log936
log369=log362+log363=log366=1 2 1 2
∵y=1.5x在R上单调递增,y=0.8x在R上单调递减,
∴1.5a=1.5
>1.50=1,0.8b=0.83 2
<0.80=11 2
即1.5a>0.8b