问题
填空题
已知Sn=
|
答案
∵Sn=
+1 1×2
+1 2×3
+…+1 3×4 1 n×(n+1)
=1-
+1 2
-1 2
+…+1 3
-1 n 1 n+1
=1-
=1 n+1 n n+1
∴
=n n+1 2008 2009
∴n=2008
故答案为:2008
已知Sn=
|
∵Sn=
+1 1×2
+1 2×3
+…+1 3×4 1 n×(n+1)
=1-
+1 2
-1 2
+…+1 3
-1 n 1 n+1
=1-
=1 n+1 n n+1
∴
=n n+1 2008 2009
∴n=2008
故答案为:2008