问题
选择题
数列{an)的前n项和为Sn,若an=
|
答案
∵an=
=1 n(n+1)
-1 n
,1 n+1
∴S2012=a1+a2+…+a2012
=(1-
)+(1 2
-1 2
)+…+(1 3
-1 2012
)1 2013
=1-1 2013
=
.2012 2013
故选D.
数列{an)的前n项和为Sn,若an=
|
∵an=
=1 n(n+1)
-1 n
,1 n+1
∴S2012=a1+a2+…+a2012
=(1-
)+(1 2
-1 2
)+…+(1 3
-1 2012
)1 2013
=1-1 2013
=
.2012 2013
故选D.